山东省青岛地区2021-2022学年高二下学期期中考试数学试题答案
2021—2022 学年度第二学期期中学业水平检测
高二数学答案及评分标准
一、单项选择题:本大题共 8小题.每小题 5分,共 40 分.
A D C A B A C D
二、多项选择题:本大题共 4小题.每小题 5分,共 20 分.
9.AC; 10.BC; 11.BD; 12.ACD.
三、填空题:本大题共 4小题,每小题 5分,共 20 分.
13.; 14.; 15.; 16.;.
四、解答题:本大题共 6小题,共 70 分,解答应写出文字说明、证明过程或演算步骤.
17.(本小题满分 10 分)
解:选择条件①:
(1)设切点为 ·····································································································1 分
因为 ,所以 ·················································································3 分
所以切线的斜率为 ······················································································4 分
解得 ····························································································································· 5 分
所以切点为 ················································································································6 分
(2)由(1)知切点为 ,
因为点 在直线 上························································································8 分
所以 ,即 ······································································································10 分
选择条件②:
(1)设切点设切点为 ······················································································1 分
因为 ,所以 ···············································································3 分
所以切线的斜率为 ······················································································4 分
解得 ······························································································································ 5 分
所以切点为 ················································································································6 分
(2)由(1)知切点为
因为点 在直线 上························································································8 分
所以 ,即 ···································································································10 分
18. (本小题满分 12 分)
解:(1)根据图可得,女生中得分不超过 分的人数 ,
女生得分超过 分的人数 ,
男生中得分不超过 分的人数 ,男生得分超过 分的人数 ,
则列联表为:
性别
了解航空航天知识程度
合计
得分不超过 分的人数 得分超过 分的人数
女生
男生
合计
······················································································3 分
(2)因为
····················6 分
所以,依据 的独立性检验,认为该学校高中生了解航空航天知识程度与性别有关联,
此推断犯错误的概率不大于 .···················································································7 分
(3)由(1)可得,得分超过 分的学生中男生:女生 ,
从得分超过 分的同学中采用分层抽样的方法抽取 人,
则男生占 人,女生占 人···································································································8 分
则 取值可能为 , ,
, , ,
所以随机变量 的分布列为
········································································································11 分
所以 .···········································································12 分
19.(本小题满分 12 分)
解:(1)设 “取出的 球中有红球”, “第 次取出的是红球” ················1 分
(ⅰ)由题意知,随机试验为从 号箱中不放回的进行 次取球
则················································································································ 2 分
又···························································································3 分
所以由古典概型的概率公式得,
故故所求的概率为 ···········································································································4 分
(ⅱ)因为 ···············································································5 分
所以由条件概率公式得,
故所求的概率为 ···············································································································6 分
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