湖南省常德市2022-2023高三上学期期末检测答案

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2022-2023 学年度上学期常德市高三检测考试
数 学(参考答案)
一、选择题:本题共 8小题,每小题 5分,共 40 分.
题号 1 2 3 4 5 6 7 8
答案 B A D D A A C B
二、选择题:本题共 4小题,每小题 5分,共 20 分.全部选对的得 5分,部分选对的得 2分,有选错
的得 0.
题号 9 10 11 12
答案 BD BC BCD ABC
三、填空题:本题共 4小题,每小题 5分,共 20 分.
13. 14. 15. 16.
三、解答题:本大题共 70 分,解答应写出文字说明、证明过程或演算步骤.
17. (本小题满分 10 )
解:(1) , ·····································································2
是以 为首项, 为公比的等比数列················································5
(2)(1)可得: ,
即: ······················································································.8
,当 n时, , 单调递增;
又 ,
满足不等式的最大整数 ·········································································10
18.(本小题满分 12 分)
解:(1)在 中,由余弦定理得 ·····························1
在 中,由余弦定理得 ································2
有, ,解得 ·············································3
,又 , ···································4
梯形 的面积
·································6
法二:(1)BC 的中点 E,连 AE,则 BE=CE=2·················································1
AD=ECAD//EC 四边形 AECD 为平行四边形···········································2
AE=DC=2·······························································································3
在 中,
········································································4
梯形 的面积 ·······················6
(2)设 , ,则
中,由正弦定理得 ,即 ①
中,由正弦定理得 ,即 ····························8
①②得: ············································································9
化简得,
所以 ························································································11
所以 为直角三角形·····················································12
法二:取 BC 的中点 E,连 AE,则 BE=CE=2
AD=ECAD//EC 四边形 AECD 为平行四边形·················································8
·································································································10
为直角三角形··········································································12
19.(本小题满分 12 分)
(1)证明:取 DE 的中点 M,连 MGMH····································································1
·············································································2
,又 平面 CGF
····························································································3
,又 平面 CGF
·····························································································4
·····················································································5
(2)如图,以 C为原点,CB x轴,CF y轴,CD z轴建立空间直角坐标系,
A(2,0,2)C(0,0,0)F(0,2,0)G(1,1,2)H(1,0,0)E(0,2,2)···································6
,设面 CGF 的法向量
令 得 ,
·······································8
··········9
设所求线面角为 ,
········································11
所以当 时, 取得最大值为 ······························································12
20.(本小题满分 12 分)
解:(1)仅乘坐一站的乘客有 10+10+10+30=60 人该乘客仅乘坐一站的概率 ······2
(2)从常德上车的乘客到长沙下车的概率 ·····················································3
故这 3人到长沙下车的人数 , ······································5
X 0 1 2 3
P
························································································································7
·······························································································8
(3)记事件 A:该乘客在过益阳南站后到长沙站下车,记事件 B1:该乘客在常德站上车,记事件 B2:该乘客
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