湖南省常德市2022-2023高三上学期期末检测答案
2022-2023 学年度上学期常德市高三检测考试
数 学(参考答案)
一、选择题:本题共 8小题,每小题 5分,共 40 分.
题号 1 2 3 4 5 6 7 8
答案 B A D D A A C B
二、选择题:本题共 4小题,每小题 5分,共 20 分.全部选对的得 5分,部分选对的得 2分,有选错
的得 0分.
题号 9 10 11 12
答案 BD BC BCD ABC
三、填空题:本题共 4小题,每小题 5分,共 20 分.
13. 14. 15. 16.
三、解答题:本大题共 70 分,解答应写出文字说明、证明过程或演算步骤.
17. (本小题满分 10 分)
解:(1) , ·····································································2 分
,
是以 为首项, 为公比的等比数列················································5 分
(2)由(1)可得: ,
即: ······················································································.8 分
令 ,当 n时, , 单调递增;
又 , ,
满足不等式的最大整数 ·········································································10 分
18.(本小题满分 12 分)
解:(1)在 中,由余弦定理得 ·····························1 分
在 中,由余弦定理得 ································2 分
由 有, ,解得 ·············································3 分
,又 , ···································4 分
梯形 的面积
·································6 分
法二:(1)取BC 的中点 E,连 AE,则 BE=CE=2·················································1 分
AD=EC,AD//EC, 四边形 AECD 为平行四边形···········································2 分
AE=DC=2·······························································································3 分
在 中,
又,········································································4 分
梯形 的面积 ·······················6 分
(2)设 , ,则 , ,
在中,由正弦定理得 ,即 ①
在中,由正弦定理得 ,即 ②····························8 分
由①②得: ············································································9 分
化简得,
又
所以 ························································································11 分
又
所以 , , 为直角三角形·····················································12 分
法二:取 BC 的中点 E,连 AE,则 BE=CE=2
AD=EC,AD//EC, 四边形 AECD 为平行四边形·················································8 分
·································································································10 分
,为直角三角形··········································································12 分
19.(本小题满分 12 分)
(1)证明:取 DE 的中点 M,连 MG、MH····································································1 分
·············································································2 分
,又 平面 CGF
····························································································3 分
,又 平面 CGF
·····························································································4 分
·····················································································5 分
(2)如图,以 C为原点,CB 为x轴,CF 为y轴,CD 为z轴建立空间直角坐标系,
则A(2,0,2),C(0,0,0),F(0,2,0),G(―1,1,2),H(1,0,0),E(0,2,2)···································6 分
则,设面 CGF 的法向量
令 得 ,
即·······································8 分
··········9 分
设所求线面角为 ,
则········································11 分
所以当 时, 取得最大值为 ······························································12 分
20.(本小题满分 12 分)
解:(1)仅乘坐一站的乘客有 10+10+10+30=60 人该乘客仅乘坐一站的概率 ······2 分
(2)从常德上车的乘客到长沙下车的概率 ·····················································3 分
故这 3人到长沙下车的人数 , ······································5 分
X 0 1 2 3
P
························································································································7 分
·······························································································8 分
(3)记事件 A:该乘客在过益阳南站后到长沙站下车,记事件 B1:该乘客在常德站上车,记事件 B2:该乘客
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