山东省烟台市2020-2021学年高一下学期期末考试数学试题答案20210624
高一数学参考答案 第1页 (共5页)
A
B
C
D
E
F
G
H
2020-2021 学年度第二学期期末学业水平诊断
高一数学参考答案
一、选择题
C A C D B C D A
二、选择题
9.AC 10.BCD 11.ABD 12.ACD
三、填空题
13.
0.94
14.
366
6
15.
222 2
ABC ACD ADB BCD
SSS S
∆∆∆ ∆
++=
16.
28
3
π
四、解答题
17.证 明 :( 1)连接
BD
,因为
,
EF
分别为棱
,AB AD
的中点,
所以
11
// ,
22
EF BD EF BD=
. ································· 2分
同理
11
// ,
22
HG BD HG BD=
. ································ 4分
所以
//
EF GH
且
EF GH=
. ·································· 5分
所以四边形
EFGH
是平行四边形. ···························· 6分
(2)当
AC BD⊥
且
AC BD=
时,四边形
EFGH
为正方形. ·····················
10 分
18.解 :( 1)设事件
,,,ABC D
分别表示“被评为等级
,,,ABC D
”.
由题意,事件
,,,ABC D
两两互斥,
所以
31 3 1
()14 8 32 32
PD =−−− =
. ························································· 2分
又
CD=
“延迟送达且被罚款”,
所以
1
( ) () () 8
PC D PC PD
=+=
. ······················································ 4分
因此“延迟送达且被罚款”的概率为
1
8
. ················································· 5分
高一数学参考答案 第2页 (共5页)
(2)设事件
,,,
iii i
ABC D
表示“第
i
单被评为等级
,,,ABCD
”,
1, 2i=
.
则“两单共获得的奖励为
0
元”即事件
22 12 21
( )( )( )A B AC AC
, ············· 7分
且事件
22 12 21
,,A B AC AC
互斥,
又
22
11 1
()
8 8 64
P AB =×=
. ···································································· 8分
又
12 21
33 9
()()
4 32 128
PAC PAC= =×=
. ·················································· 9分
所以
22 12 21
[( ) ( ) ( )]P P A B AC A C
=
22 12 21
( )( )( )
PAB PAC PAC= ++
·············································· 10 分
11 3 3 5
2
8 8 4 32 32
=×+× ×=
.·························································
12 分
19.解:( 1)由题意,
4357 611798694
40
y×+×+× +×+×+×
=
··········································· 2分
6.5=
. ·························································································· 3分
2 22 2
1[3 (4 6.5) 7 (5 6.5) 11 (6 6.5)
40
y
s= ×− +×− +×−
222
9 (7 6.5) 6 (8 6.5) 4 (9 6.5) ]+×−+×−+×−
······························· 5 分
1.95=
. ························································································ 6分
(2)由(1)可得,
1(50 40 )
90
z xy= +
······················································ 8分
1(50 7.4 40 6.5) 7
90
= × +× =
. ····································· 9分
22 2
50 40
[2.6 (7.4 7) ] [1.95 (6.5 7) ]
90 90
z
s= + − +× + −
································· 11 分
113
45
=
. ·················································································· 12 分
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