《山东中考真题数学》2022年山东省淄博市中考数学试卷参考答案及解析

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数学试题参考答案及评分标准
一、选择题:本大题共 12 个小题,每小题 5分,共 60 分。
题目 1 2 3 4 5 6 7 8 9 10 11 12
题号 A D C D B A C C D B A B
二、填空题:本大题共 5个小题,每小题 4分,共 20 分。
13a5 14xx+3)(x—3 15.(13 16.—2 17.(—20232022
三、解答题:本大题共 7个小题,共 70 分。
18(本题满分 8 分)
解:整理方程组得 ·········································2
×2—② 得—7y=7
y=1····································································4
y=1 代入①得 x—2=3
解得 x=5································································6
∴方程组的解为 . ··················································8
19(本题满分 8 分)
证明:∵△ABC 是等腰三角形,
∴∠EBC=∠DCB·······················································2
在△EBC 与△DCB 中,
BE=CDBC=CB
EBC≌△DCB(SAS)··················································6
BDCE······························································8
20(本题满分 10 分)
解:(1)将点 A ( 12 )代入 y =,得 m=2
双曲线的表达式为:y···············································1
A12)和 B40)代入 ykx+b得:
y,解得: ,·········································3
直线的表达式为:yx+·········································4
2)联立 ,解得 ,或 ·························5
A 的坐标为(12),
B的坐标为(3, ), ···············································6
SAOB= SAOB SAOB= OC· OC·
= ×4×2— ×4×
=
∴△AOB 的面积为 ···················································8
31<m<3····························································10
21(本题满分 10 分)
解:(1120 99 ························································4
2)如图:
··············8
3)把“礼仪”“陶艺”“园艺”“厨艺”及“编程”等五门校本课程分别记为
ABCDE,画树状图如下:
共有 25 种等可能的结果,其中小刚和小强两人恰好选到同一门课程的结果有 5种,
∴小刚和小强两人恰好选到同—门课程的概率 P=
············································10
22(本题满分 10 分)
解:小明能运用以上数据,得到综合楼的高度,理由如下:
EGAB,垂足为 G,作 AHCD,垂足为 H,如图:
····················2
EG= BF= 40 EF= BG= 12.88 HAE= 16°= AEG= 16°CAH
=9°
RtAEG 中,
tan AEG=
tan 16°= ,即 0.287≈ ············································4
AG = 40×0.287=11.48(米),
AB = AG+BG=11.48+12.88= 24.36(米),····································6
HD= AB =24.36 米,
RtACH 中,AH =BD= BFFD=80 米,
22 题答案图
《山东中考真题数学》2022年山东省淄博市中考数学试卷参考答案及解析.docx

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