(福建南平)2020-2021学年第一学期八年级期中测试-数学试题卷(人教版)参考答案及评分建议
八年级数学参考答案第 1页(共 6页)
2020-2021 学年第一学期八年级期中测试-数学试题卷
参考答案及评分建议
一、选择题:本题共 10 小题,每小题 4分,共 40 分.
1
2
3
4
5
6
7
8
9
10
B
C
A
C
D
B
A
D
C
D
二、填空题:本题共 6小题,每小题 4分,共 24 分.
11.九 12.20°
13.15 14.16
15.= 16.8
三、解答题:本题共 9小题,共 86 分.
17.(本小题满分 8分)
证明:∵∠BAD=∠CAE,
∴∠BAD+∠DAC=∠CAE+∠DAC,
即∠BAC=∠DAE. ············································································· 2 分
在△ABC 和△ADE 中,
BAC DAE
AB AD
BD
, ············································································· 5 分
∴△ABC≌△ADE(ASA). ···································································· 6 分
∴BC=DE. ······················································································· 8 分
18.(本小题满分 8分)
解:(1)如图,△A′B′C′即为所求.
···························································· 5 分
(2)A′(2,3) B′(3,1) C′(-1,-2) ························································ 8 分
19.(本小题满分 8分)
证明:∵AD⊥BC,
∴∠BDF=∠ADC=90°. ······································································· 2 分
∵∠ABC=45°,
∴∠BAD=∠ABC=45°,
∴BD=AD. ······················································································· 4 分
∵AD⊥BC,BE⊥AC,
∴∠C+∠DAC=90°,∠C+∠CBE=90°,
八年级数学参考答案第 2页(共 6页)
∴∠CBE=∠DAC. ············································································· 6 分
在△BDF 和△ADC 中,
CBE DAC
BD AD
BDF ADC
, ············································································ 7 分
∴△BDF≌△ADC(ASA). ···································································· 8 分
20.(本小题满分 8分)
证明:∵AD 是∠BAC 的平分线,DE⊥AB,DF⊥AC,
∴DE=DF,∠AED=∠AFD=90°,∠EAD=∠FAD,
∴点 D在EF 的垂直平分线上. ····························································· 2 分
在△AED 和△AFD 中,
AED AFD
EAD FAD
AD AD
,
∴△AED≌△AFD(AAS), ···································································· 4 分
∴AE=AF,
∴点 A在EF 的垂直平分线上, ····························································· 6 分
∴AD 所在直线是 EF 的垂直平分线,
即AD 垂直平分 EF. ··········································································· 8 分
21.(本小题满分 8分)
解:(1)如图,DE 所在直线是 AC 的垂直平分线.
························································ 3 分
(2)如上图,连接 AD.
∵AB=AC,∠BAC=120°
,
∴∠C=∠B=30°
. ············································································ 4 分
由(1)知,DE 所在直线是 AC 的垂直平分线,
∴AD=CD, ···················································································· 5 分
∴∠DAC=∠C=30°
,
∴AD=CD=2DE,∠BAD=120°
-30°=90°
, ············································ 6 分
∴△ABD 是直角三角形,且∠B=30°
,
∴BD=2AD=4DE.
∵DE=2 cm,
∴CD=4 cm,BD=8 cm,
∴BC=BD+CD=12 cm,
即BC 的长为 12 cm. ······································································· 8 分
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